(3x)(x+10)=6x^2

Solution for (3x)(x+10)=6x^2 equation:

(3x)(x+10)=6x^2

We move all terms to the left:

(3x)(x+10)-(6x^2)=0

determiningTheFunctionDomain
-6x^2+3x(x+10)=0

We multiply parentheses

-6x^2+3x^2+30x=0

We add all the numbers together, and all the variables

-3x^2+30x=0

a = -3; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-3)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-3}=\frac{-60}{-6}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-3}=\frac{0}{-6}
=0
$